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Why is polynomial convolution equivalent to multiplication in $F[x]/(x^n-1)$?

From this, I still can not understand how to get this $$ \begin{align} &f*g +(x^n-1)\sum_{k=0}^{n-1}\sum_{i+j=k+n}f_ig_jx^k \end{align} $$

from $$ \begin{align} \sum_{k=0}^{n-1}\left(\sum_{i+j=k}f_ig_j+\sum_{i+j=k+n}f_ig_jx^n\right)x^k\\ \end{align} $$

Thanks for answers.

Bobby
  • 11

0 Answers0