I have the following integral that I need to solve.
$\int_{-\infty}^\infty \exp(-\frac{x^2}{2})*\text{erf}(x-\delta)*\text{erf}(x-\gamma)dx$
I was hoping I could use this: Integral of product of exponential function and two complementary error functions (erfc)
and 4.3-2 here: http://nvlpubs.nist.gov/nistpubs/jres/73B/jresv73Bn1p1_A1b.pdf.
And since $\int_{-\infty}^\infty \text{erf}(x)^2\text{exp}(-x^2/2)=\frac{1}{2}\int_{0}^\infty \text{erf}(x)^2\text{exp}(-x^2/2)$.... the result is easy to get.
– Klein Gordon May 14 '15 at 12:08