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Actually ,I am trying to execute the algorithm to find the power of generator of field(group) as shown in table of attached file but when k=7 and onward ,I could not understand what is going on.so please explain the logic.
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I use the same polynomial in the third section of this answer I designed with referrals like this in mind. The difference is that I used $\gamma$ instead of $u$. Scroll down that answer to get to the part with a lot of $\gamma$s :-) The idea is that whenever the multiplication forces $\gamma^4$ (or $u^4$) to appear, you replace it with $\gamma+1$ (or $u+1$), and continue. – Jyrki Lahtonen May 05 '15 at 20:25
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@JyrkiLahtonen:Thank you very much,now I got the exact logic what I wanted. – AJAY KUMAR May 06 '15 at 05:40
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Please put that as an answer: since this question shows up in the list of unanswered questions. – Alex May 09 '15 at 19:25