Prove that square of even integer is even.

Question

Is my proof correct?

Suppose $n=2m$ is an even integer. Since $n=2m$ , then $n^{2}=(2m)^{2}$

$n^{2}$ = $(2m)^{2}$ = $4m^{2}$

=$2(2m^{2)}$

Since $(2m^{2})$ is an integer and $2(2m^{2})$ is in the form $2m$ , we have proven that the square of an even integer is even.

score 7 · Accepted Answer · answered Apr 18 '15 at 00:56

7

Yes, that is pretty much it. Good job.

answered Apr 18 '15 at 00:56

Ivo Terek

3

Who downvotes a perfectly good answer? – Cameron Buie Apr 18 '15 at 01:02
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And I even made the answer CW to not gain unfair rep! :P – Ivo Terek Apr 18 '15 at 01:03

1 Answers1