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Let $K$ be the surface of an infinite cone with circular cross section, vertex at the origin and axis lying along the positive $z$-axis. If the angle between the $z$-axis and the surface of the cone is $α$, find expressions for $K$ in terms of Cartesian, spherical and cylindrical polar coordinates.

Solution:

In terms of spherical polars, $K = \{(ρ,ϕ,θ) : 0 \leq ρ < ∞,ϕ = α,0 \leq θ < 2π\}$. By simple trigonometry, $tanα = r/z = (\sqrt{x^2 + y^2})/z$. In terms of Cartesian coodinates then, $K = \{(x,y,z) : x^2 +y^2 = z \tan α\}$ and, in terms of cylindrical polars, $K = \{(r,θ,z) : r = z tanα,0 \leq θ < 2π\}$.

For the Cartesian, shouldn't it say $(z \tan α)^2$ instead, since it is the radius?

snowman
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1 Answers1

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You are right, in terms of cartesian coordinates it should be $$z \tan(\alpha) = \sqrt{x^2+y^2}.$$

Mark Fantini
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