the theorem states that if f(x) can be expanded as a power series for a given range of values of x then:
$$f(x)=f(0)+xf'(0)+\frac{x^2}{2!}f''(0)+\frac{x^3}{3!}f'''(0)+\cdots$$
($'$ means derivative) if $f(x)=\tan(x)$, what is the power series?
the theorem states that if f(x) can be expanded as a power series for a given range of values of x then:
$$f(x)=f(0)+xf'(0)+\frac{x^2}{2!}f''(0)+\frac{x^3}{3!}f'''(0)+\cdots$$
($'$ means derivative) if $f(x)=\tan(x)$, what is the power series?
The right name of the theorem -> Taylor-McLaurin
How to format equations on M.SE -> Mathjax
And an answer to your question (given by googling "mclaurin tan") -> here (where $B_n$ is the $n$-th Bernoulli number)