How to prove that $$\displaystyle\lim_{n\to\infty}\sum_{k=1}^n\left(\frac{k}{n}\right)^n=\frac{e}{e-1}$$
Thank in advances.
How to prove that $$\displaystyle\lim_{n\to\infty}\sum_{k=1}^n\left(\frac{k}{n}\right)^n=\frac{e}{e-1}$$
Thank in advances.