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I have two questions:

1) How to deduce the irreducible factors of $x^4 +1$ in $\Bbb F_3$. Clearly the irreducible factors will be of degree $2$. But can anyone calculate it for me?

2) I have proved that if $f,g \in F[x]$ are irreducible polynomials of the same degree in a finite field $F$, then they have the same splitting field. Now using this how can I find the splitting field of $x^4 +1$?

user26857
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Ri-Li
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1 Answers1

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For the irreducibility part:

You can easily see that $x^4+1$ has no lineal factors so the only posibility will be two factors of degree 2.

Consider a monic polynomial in your field:

$f(x)=x^2+ax+b$

This polynomial is irreducible iff has no solutions in $\mathbb{F}_3$ so we have the following result:

$f$ is irreducible iff these conditions are satisfied

b$\neq$ $0$

$1+a+b\neq$ $0$

$4+2a+b\neq$ $0$

Now check if your polynial can be written as product of polynomials satisfying these conditions.

Every finite field extension is normal so if you add one root of your polynomial you'll get the splitting field

$\mathbb{F}_3$[$\alpha$] is a normal extension of $\mathbb{F}_3$ $\implies$ $\mathbb{F}_3$[$\alpha$] is the splitting field of the polynomial

Abellan
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