Does anyone know the solution to the Ito integral with the scaling factor on $dW_t$ being $\frac{1}{w_t}$? In other words what is:
$\int \frac{dW_t}{W_t}$ ?
It looks dangerously close to what mathemattical finance people do when they look at geometric Brownian motion, but they start with the assumption that the price, $S_t$ follows an exponential trajectory of the form:
$S_t=S_0e^{((\mu -\frac{1}{2}\sigma^2)t+\sigma W_t)}$
so, when they take the natural log the $e^{(-)}$ falls away.
My brain may just be failing, but I think this does not help find $\int \frac{dW_t}{W_t}$.
In fact, I am curious if there is a 'standard' (cookbook) way of getting the integral of any polynomial Brownian motin, i.e., $\int (W_t)^kdW_t$, but $k=-1$ is fine for now...