Say, I'm comparing two functions
$f(n) = (ln(n))^2$ and $ g(n) = n^{0.01}$
as $n \rightarrow \infty$, by evaluating
$\lim_{n \rightarrow \infty } \frac{f(n)}{g(n)} = \lim_{n \rightarrow \infty } \frac{ln(n)^2}{n^{0.01}} $.
My question:
Am I justified in simplifying this by expressing $n$ as a function of $x \in \Re$, such that
$n(x) = e^x$,
so that the original limit becomes
$\lim_{x \rightarrow \infty } \frac{f(n(x))}{g(n(x))} = \lim_{x \rightarrow \infty } \frac{x^2}{e^{0.01x}} $ ?
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adeelh
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For the functions that you see most commonly, that would be OK. Be careful when the functions vary a lot near $\infty$, such as $(x+\sin(x))/\cos(x)$. But, for simple functions like exponentials and powers, it'll work. – Michael Burr Mar 06 '15 at 13:13
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There is a complete discussion about the circumstances in which you can do this type of substitution here. – rnrstopstraffic Mar 06 '15 at 16:16
1 Answers
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The function $n=e^x$ is monotone, so it's justified. In this specific example you don't need to do it: $$ \lim_{n \to \infty} \frac{\log^a n}{n^s} = 0 $$
where $a,s>0$

Alex
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