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How to show that $$A=\begin{pmatrix}1233&2344&1324&3456\\ 2342&11233&1432&13256\\234132&32432&1234567&43254\\423412&42354&452356&13245\end{pmatrix}$$ is invertible ? I could compute the determinant, but it's very very long...

Casteels
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idm
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  • @SamiBen: Oh, true, I had already seen this link long times ago, but I had totally forgot the way to solve it. Thanks. – idm Feb 25 '15 at 12:15

1 Answers1

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If you take the coefficients modulo 2, you see that there is only $1$ on the diagonal and $0$ elsewhere. Therefore $$\det A\equiv 1\pmod 2,$$ and thus $\det A$ is odd. Therefore $\det A\neq 0$ and thus $A$ is invertible.

Surb
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