Can I define the quotient group $\mathbb{Q}/\mathbb{Z}$ under addition as $\{\frac{a}{b}|a,b\in\mathbb{Z}\}$ or is that wrong? How would you define it?
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I meant the quotient group under addition – charles_xavier Feb 18 '15 at 12:36
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1So you didn't mean all rational numbers except for integers? – barak manos Feb 18 '15 at 12:38
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i edited the question – charles_xavier Feb 18 '15 at 12:39
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Can you please describe this set in plain English? – barak manos Feb 18 '15 at 12:41
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@barakmanos the quotient group of the rational numbers (with addition as operation) by the subgroup of integers. See the defintion of Quotient Group if necessary. – quid Feb 18 '15 at 12:46
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2What you have written is wrong. The set of elements of ${\mathbb Q}/{\mathbb Z}$ is equal to the set of cosets ${\frac{a}{b} + {\mathbb Z} \mid a,b \in {\mathbb Z}, b \ne 0 }$. – Derek Holt Feb 18 '15 at 13:01
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$p/q$ ~ $p/q + z, \forall z \in \mathbb{Z}$ – Vinícius Ferraz Feb 18 '15 at 14:40
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It is the rational circle group. – Bill Dubuque Feb 18 '15 at 15:05
2 Answers
The set under consideration is as you say the quotient group of the rationals with addition by the integers.
Taken strictly its elements are equivalence classes of rational numbers, so $$\mathbb{Q}/\mathbb{Z} = \{[q] \colon q \in \mathbb{Q} \}$$ where $[q] = \{q' \in \mathbb{Q} \colon q - q' \in \mathbb{Z}\}$.
Having said this what you mean is perhaps a set of representative of the classes, here you could take all rationals $q$ such that $0 \le q <1$, or staying with your notation all $a/b$ with a nonzero natural number $b$ and $0 \le a < b$ also natural (and $\gcd(a,b)=1$ if you want to eliminate duplicates).
However if you do this you need to be carful how you define your operation: you could say for $0 \le q,q' < 1$ you have $q\oplus q' = q + q'$ if $q+q'<1$ and $q\oplus q' = q + q' - 1$ if $1\le q+q'$ (note that $q + q'$ is always less than $2$); here I denote by $\oplus$ the operation on your set of representatives and by $+$ the usual addition in the rationals.

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The correct definition of $\mathbb{Q}/\mathbb{Z}$ is given by taking $\mathbb{Q}$ and identifying elements $a,b\in\mathbb{Q}$ whenever $a-b\in\mathbb{Z}$.
You can make the identification $$\mathbb{Q}/\mathbb{Z} = \{e^{2i\pi t}\in\mathbb{C}|t\in\mathbb{Q}\}\subset S^1$$ the "rational points" in the (complex) unit circle.

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