It is a matter of basic linear algebra to get the answer. Let me
reformulate the question.
Let $s_{\cdot}$ be the Schur polynomials and $c_{i,j}^k$ be
the Littlewood-Richardson coefficients. Namely, with Einstein
summation convention, $$s_{i}s_{j} = c_{i,j}^{k} s_{k}$$
Let $m_{\cdot}$ be the symmetric monomials and $d_{a,b}^c$ be
such that $$m_{a}m_{b} = d_{a,b}^{c} m_{c}.$$
We want an expression of the $d$'s in terms of the $c$'s.
Deduction
It is wellknown that both $s$ and $m$ forms a basis for the ring
of symmetric function over $\mathbb{Q}$. So there are matrices
$P, Q$ inverse to each other such that $m_a = P_a^i s_i$ and $s_i
= Q_i^a m_a$ for any $a$ and $i$.
Then $m_a m_b$ equals $(P_a^i s_i)(P_b^j s_j)$, so
$$P_a^i P_b^j c_{i,j}^k = d_{a,b}^c P_c^k.$$
Since $Q$ is the inverse of $P$, we have the formula
$$d_{a,b}^c = P_a^i P_b^j Q_k^c c_{i,j}^k.$$