Find $\lim_\limits{x\to \infty}{\sqrt[3]{x^3+ax^2+bx+c}-x}$. As I understand, I should use Taylor series, but I don't know how. What should I translate into Taylor series, to what extent, etc. This is the formula I know: $f(x)=\sum_{j=0}^{\infty}{f^{(j)}(x_0)\over j!}(x-x_0)^j+o((x-x_0)^n)$. I would really appreciate your help.
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This is more about the series than about the limit. – Meitar Abarbanel Jan 29 '15 at 02:05
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Does the answer using Taylor series at the linked question help you? (Ctrl f to find "Taylor" quickly) – Jonas Meyer Jan 29 '15 at 02:06
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1Actually, yes. For the first time I see it was fully explained. – Meitar Abarbanel Jan 29 '15 at 02:09