Looking at Pascal's triangle, it looks as though all rational numbers can also be expressed as binomial coefficients. Given a rational integer, is it possible to calculate n & k for the binomial coefficient that will evaluate to it?
Asked
Active
Viewed 39 times
1
-
1Rational integer??? – barak manos Jan 25 '15 at 17:58
-
${n\choose 1} = n$ for all integers $n \ge 1$. – TonyK Jan 25 '15 at 18:29
-
@GeorgeV.Williams Yup, that's exactly what I wanted to know. Thanks – Joel Jan 25 '15 at 19:05