I'm trying to find the orbits of the Frobenius homomorphism $\phi_p: a \to a^p$ on $\mathbb{F}_{p^4} / \mathbb{F}_p$. I can see there are $p$ 1 orbits corresponding to the action on $\mathbb{F}_p$ but I think there are also some order 2 and 4 orbits but I'm having trouble finding how many of each there are.
This is part of an argument on trying to show how many irreducible polynomials of degree 4 there are over $\mathbb{F}_p$ because I think this number should correspond to how many order 4 orbits there are, as then the polynomial with roots in that orbit should be irreducible.
Thanks
The main theorem is: In $ \mathbb{F}_q$ where $q = p^r$ for $p$ prime and $r\gt 0$, $t^{q^m} - t $ is the product of all normalized irreducible polynomials $ f \in \mathbb{F}_q [t]$ where $\deg f | m $.
– kummerer94 Jan 06 '15 at 22:06