Show that a monotone or differentiable function $h:[a,b] \to \mathbb R$ is of bounded variation on $[a, b]$.
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In both cases you can compute bounded variation directly. Start with the monotone case: what do all the absolute values turn into? – SBF Dec 10 '14 at 07:46
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2You need more than just differentiability. See this. – David Mitra Dec 10 '14 at 07:48
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Suppose $h$ is monotone increasing. Let $P = (x_0,x_1,\ldots,x_n)$ be a partition of $[a,b]$.
Then
$$V_a^b(h) = \sup_{P}\sum_{k=1}^n |h(x_k) - h(x_{k-1)}|=\sup_{P}\sum_{k=1}^n \left(h(x_k) - h(x_{k-1)}\right)= h(b) - h(a).$$
If $h$ is monotone decreasing, then make a similar argument.
If $h$ is differentiable with a bounded derivative $|h'(x)| \leqslant M$, then using the MVT, there exist points $x_{k-1} \leqslant \xi_k \leqslant x_k$ such that
$$V_a^b(h) = \sup_{P}\sum_{k=1}^n |h(x_k) - h(x_{k-1)}|=\sup_{P}\sum_{k=1}^n |h'(\xi_k)|\left|x_k - x_{k-1}\right|\\ \leqslant \sup_{P}\sum_{k=1}^n M\left|x_k - x_{k-1}\right|= M[b - a].$$

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