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I am going mixed
Asked
Dec 09 '14 at 20:13
Active
Dec 09 '14 at 21:13
Viewed
46 times
1
Why this is wrong ?
$ -1=(-1)^{2/2}=((-1)^{2})^{1/2}=1^{1/2}=1 $
Then
$1=-1$
linear-algebra
asked Dec 09 '14 at 20:13
1
the folks at math.stackexchange will tell you $(-1)^{2/2}\neq((-1)^2)^{1/2}$
–
QuantumDot
Dec 09 '14 at 20:17
Why it is not equal.
–
Dec 09 '14 at 20:18
1^(1/2)=+/-1. you then take the -1 to match the LHS.
–
Basheer Algohi
Dec 09 '14 at 20:19
$((a)^{m})^{n}=((a)^{n})^{m}$
–
Dec 09 '14 at 20:19
Step 2 -> Step 3 is wrong. The
Order
of evaluation matters.
–
Chen Stats Yu
Dec 09 '14 at 20:50
2
@YvesKlett And also for the title... :)
–
sebhofer
Dec 09 '14 at 21:06
LOL the tags are awesome.
–
DumpsterDoofus
Dec 09 '14 at 21:12
@Masoud The rule $(a^m)^n = a^{mn}$ is not true for all $a$, $m$, $n$. Generally when that rule is taught, these variables are assumed to be positive.
–
Greg Hurst
Dec 09 '14 at 21:29
0 Answers
0
Order
of evaluation matters. – Chen Stats Yu Dec 09 '14 at 20:50