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Is 17x+11 a function of O(x^2)?

My steps so far:

17x+11 < c.x^2 where x>k 17x+11/x^2 < C

Im not too sure what to do next so I'd really appreciate if it someone could guide me.

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    Yeah, sometimes people here are too quick on the closing trigger. You want a $c > 0$ such that $17x+11<cx^2$ for all $x>k$. Since $x^2$ grows much faster than $17x$, try $c=1$. Then $17x+11<x^2$ is equivalent to saying $x^2-17x-11>0$. A little algebra will tell you that this is true for all $x>(17+\sqrt{289+44})/2\approx 17.62$ so $k=18$ will work here. – Rick Decker Sep 27 '15 at 22:52
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