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Given a partial ordered set (poset) $S$, is there a known procedure or algorithm to find the set of chains (i.e. subsets of $S$ where every two elements are comparable)?

Note: I am asking here instead of math.SE because i'm looking for an algorithm for the problem.

Juho
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seteropere
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1 Answers1

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Yes there is, have a look at :

Chen, Yangjun, and Yibin Chen. "On the Decomposition of Posets." Computer Science & Service System (CSSS), 2012 International Conference on. IEEE, 2012.

and also this:

Daskalakis, C., Karp, R. M., Mossel, E., Riesenfeld, S. J., & Verbin, E. (2011). Sorting and selection in posets. SIAM Journal on Computing, 40(3), 597-622.

AJed
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    Please lay out the ideas of the algorithms here; the first paper is paywalled. – Raphael Apr 14 '13 at 10:32
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    There are many details in both papers, which I dont think I have time to cover. If someone would like to volunteer, I will appreciate it. The second paper is well-written and easy. I think just mentioning the paper titles here as an answer to this question will be benificial to the reader. Because the question is: is there an algorithm ... my answer was YES – AJed Apr 14 '13 at 15:35
  • On the other hand, can I attach files to answers. I have a soft-copy of both papers. – AJed Apr 14 '13 at 15:36
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    No, we can't do that. I think it's debatable whether two references constitute an answer (as opposed to a comment). They are clearly useful, but SE policy dictates answers shout contain more than just links. – Raphael Apr 14 '13 at 15:59
  • That's interesting. Then I think you should start revising many old answers. Because this answer is not the only one of its kind. See these answers here: http://cs.stackexchange.com/questions/7250/retrieving-the-shortest-path-of-a-dynamic-graph – AJed Apr 14 '13 at 20:56
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    You might note that none of the answers you link to only give references. That said, the existence of suboptimal answers does not justify more of the kind. – Raphael Apr 15 '13 at 06:59
  • @Raphael first paper is available here – LastIronStar Nov 12 '17 at 05:33