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Is the representation of the polynomial system of a symmetric cipher overdetermined?

juaninf
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    It seems trivial to make an overdetermined system of equations from one that is not. Perhaps the real question is: Can the conventional representation of the polynomial system of a symmetric cipher be overdetermined? Otherwise, I don't get it. – fgrieu Jun 09 '21 at 10:10
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    Some examples or references could help making the question more clear. As it stands it is not clear to me what the definition of "overdetermined" is, or when this happens. Without this clarity the question is in danger of being opinionated. – Maarten Bodewes Jun 09 '21 at 10:14

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