-1

I have a message m="hunter". Let's say we pad it with 2 spaces from the left making the final message as m_dash=" hunter".

We are given with c where c=pow(bytes_to_long(m_dash), 3, n) and n(1024 bit). n is too big to be factorised and therefore we can't get the totient and thus 'd'. And because of that we can't recover our padded-message trivialy by pow(c,d,n). Is there any way I can get my message back? Original messsage is bigger than 'hunter'. Can't apply cube-root attack.

Aviral Gupta
  • 1
  • 1

1 Answers1

2

Hint: $\text{bytes_to_long}(\text{m_dash})^3 < n$

poncho
  • 147,019
  • 11
  • 229
  • 360