As the title states; Is there any risk from encrypting the key with itself? EG. $C = AES(K=K, M=K)$
I'd assume not; after all, how does having the key for a safe inside the safe make it easier to pick the lock?
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Here is a similar question for the block cipher AES. – Maarten Bodewes Dec 04 '19 at 21:14
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@MaartenBodewes didn't see that one, and it and one of the answers below answer my question combined, so I'll select and mark as duplicate. – Legorooj Dec 04 '19 at 22:04