How do I find out the total no of geometrical and stereo isomers of the compound given as $\ce{C2FClBrI}$? Is there any way I can list out all the possible structures mathematically without having to think about each structure in my mind? Any suggestion how you would do it would be wonderful.
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Well, do you know what geometry this type of compounds has - you need to know symmetry of compound. – Mithoron Aug 28 '16 at 00:59
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No but id love to know the more general way to deal with having to tell the total number of isomers of any type of compound – Aug 28 '16 at 01:14
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1related http://chemistry.stackexchange.com/questions/7975/finding-the-number-of-cyclic-isomers-algorithmically?rq=1 http://chemistry.stackexchange.com/questions/16135/how-to-determine-number-of-structural-isomers http://chemistry.stackexchange.com/questions/33356/is-there-a-formula-to-determine-the-total-number-of-constitutional-isomers – Mithoron Aug 28 '16 at 01:32
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FC(I)=C(Cl)Br, FC(Br)=C(Cl)I, FC(Cl)=C(Br)I – gilleain Aug 28 '16 at 10:10