I'm doing a high-school assignment, and I came across a question that I didn't quite understand.
Explain how the electron configurations for the following elements do not follow the diagonal rule:
- Gold
- Curium
- Thorium
- Molybdenum
- Palladium
From what I understand, all of these elements do follow the diagonal rule. How exactly do they not follow this rule?
The reason for these exceptions (from the diagonal rule) is that some elements are more stable with fewer electrons in some subshells and more electrons in others:
Electronic configuration of molybdenum: $[\ce{Kr}] \ce{4d^{5} 5s^1}$, instead of $[\ce{Kr}] \ce{5s^2 4d^{4}}$ according to the diagonal rule, because a half-full $\ce{4d}$ subshell and a half full $\ce{5s}$ subshell are more stable than $\ce{4d}$ filled with four electrons and a full $\ce{5s}$ subshell.
Electronic configuration of Gold: $[\ce{Xe}] \ce{4f^14 5d^{10} 6s^1}$, instead of $[\ce{Xe}] \ce{4f^14 5d^{9} 6s^2}$ according to the diagonal rule, because a full $\ce{5d}$ and half full $\ce{6s}$ subshell is more stable than $\ce{5d}$ filled with 9 electrons and a full $\ce{6s}$ subshell.
Electronic configuration of Palladium: $[\ce{Kr}] \ce{4d^{10}}$, instead of $[\ce{Kr}]\ce{ 5s^2 4d^{8}}$ according to the diagonal rule, because a full $\ce{4d}$ orbital is more stable than $\ce{4d}$ filled with eight electrons.
Electronic configuration of Curium: $[\ce{Rn}] \ce{7s^2 5f^7 6d^{1}}$, instead of $[\ce{Rn}] \ce{7s^2 5f^8} $ according to the diagonal rule, because a half full $\ce{5f}$ orbital is more stable than $\ce{5f}$ filled with eight electrons.
