How to calculate the volume of dry hydrogen in magnesium/ HCl reaction

Asked Oct 19 '14 at 16:39

Active Nov 27 '17 at 12:24

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I am not sure if the equivalents of $\ce{H2}$ in the equation $$\ce{Mg (s) + 2HCl (aq) -> MgCl2 (aq) + H2}$$
is that of dry or wet hydrogen.

If the $\ce{H2}$ refers to wet hydrogen in the equation, how should I find the volume of dry hydrogen given the pressure of wet and dry hydrogen and the volume of wet hydrogen?

edited Nov 27 '17 at 12:24

Martin - マーチン

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asked Oct 19 '14 at 16:39

most venerable sir

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The water is a liquid. It exerts a vapor pressure. Some of the pressure in the gas is not due to hydrogen, it is due to water vapor so it is called wet hydrogen. – Brinn Belyea Oct 19 '14 at 16:58
Not a duplicate, plus the linked question does not have an answer. – Martin - マーチン Nov 27 '17 at 12:28

How to calculate the volume of dry hydrogen in magnesium/ HCl reaction

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