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The actual question in my mind is that ……..at anode zinc oxidises to form $\ce{Zn^{2+}}$ and $2$ electrons, but it should be the same case at cathode because copper should also oxidise to form $\ce{Cu^{2+}}$ and $2$ electrons. Then in this case the potential difference is zero hence there is no current flow……please clarify?

Maurice
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Physics student is wrong for two reasons. First, in the Daniell cell cathode, copper is not oxidized. It is the contrary. It is reduced from $\ce{Cu^{2+}}$ to $\ce{Cu}$, and it is reduced by the $2$ electrons produced by zinc at the anode. Second, the potential difference is not zero. It depends on the concentration of the ions in solution. But it is usually around $1$ Volt.

Maurice
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  • The copper electrode is at a different potential from the zinc electrode. Also is the Daniell cell not designed to give a well defined voltage and its use restricted to a Wheatstone bridge environment of ZERO current draw, hence a constant voltage. This could be where the confusion is arising. – jimchmst Feb 07 '24 at 22:48