I learned that alkynes gets reduced on addition of $\ce{Na}$ in liquid $\ce{NH3}$ to form alkenes (which is not further reduced). Recently I came across a reaction where a conjugated diene was treated with $\ce{Na}$ in liquid $\ce{NH3}$ .The product was what you would get by 1,4 adding $\ce{H2}$ in the conjugated diene.
Is this reaction correct? If yes ,then what makes it more reactive than an ordinary alkene?
