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I was reading about nucleophilicity and basic strength orders. I came across this interesting set of three compounds $\ce{NH3},$ $\ce{N2H4}$ and $\ce{NH2OH}$ where I am not able to apply the rules I have learnt.

The correct order of basic strength is given to be:

$K_\mathrm b$ value: $\ce{NH3} > \ce{N2H4} > \ce{NH2OH}$

The rules I know are:

  1. If the donor atom is same, then order of nucleophilicity is same as the order of basicity.
  2. Alpha effect: if the adjacent atom attached to the donating atom has lone pair of electrons, then nucleophilicity is enhanced.

When I try to conclude the nucleophilicity order, I am getting contradicting results with the above rules. Also, I wonder whether the −I effect due to the presence of highly electronegative atom may have a role to play.

So, what is the correct order of nucleophilicity of $\ce{NH3},$ $\ce{N2H4}$ and $\ce{NH2OH}?$

Is it theoretically possible to conclude the correct order based on deciding which factor will dominate in a given situation?

CLARIFICATION:

My doubt is pertaining to specifically these three compounds.Many have said that this question is a duplicate of Is there a general consensus on the causes of the alpha-effect? But, I am not able to get the order of nucleophilicity that I need from the answers to that question.I am not able to find the information on order of nucleophilicity of these three compounds in the books I use.So, it would be helpful if someone clarifies the position of $\ce{NH2OH}$ in this.

Chem-Learner
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