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Shouldn't d(x²-y²) dxy and dz² orbitals participate? Since this corressponds to the best case overlap?

What factors decide the participating orbitals in hybridisation?

P.S I am well versed with the concepts of CFT and VBT but know little to nothing about other theories lik MOT and Group theory.

user226375
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  • Learn about MOT and group theory. Hybridization is an inferior concept that should be thrown into the ash heap of history. Start here. – Oscar Lanzi May 23 '19 at 11:28
  • @OscarLanzi so this can't be explained by simple hybrididsation? – user226375 May 23 '19 at 11:38
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    Please, forget hybridisation especially for transition metals, read https://chemistry.stackexchange.com/questions/76726/why-is-it-wrong-to-use-the-concept-of-hybridization-for-transition-metal-complex . Oh and all atomic d orbitals have the same amount of nett overlap with an s function - zero, as they are eigenfunctions of the same Hermitian operator and are hence orthogonal. – Ian Bush May 23 '19 at 11:51
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    @user226375 I am not saying it can't be explained bybhybridizatiin. I am saying it shouldn't. See also the preceding comment. – Oscar Lanzi May 23 '19 at 12:31

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