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If we were in an earthlike planet at 1AU from a black hole merger, would we be able to hear the spacetime strains as the black holes orbit around each other? How would it sound?

Ahmed Ameeri
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What would be heard is vibrations set up by the gravitational wave in the atmosphere, although presumably they would also directly stimulate the parts of the ear too.

The amplitude of gravitational waves fall off as $1/r$. The proportional change in lengths near (e.g. about a Schwarzschild radius $R_S$ away) the merger is $\approx 1$. So at 1 AU it would be $R_S$/1 AU. For stellar mass black holes this makes the amplitude $\delta\approx 3\cdot 10^{-8}$.

But if we think in terms of sound pressure, the pressure in dB is $20 \log_{10}(P/P_0)$ where $P_0$ is the reference power 20 μPa in air. How do we get a pressure from displacements? This Wikipedia page gives an expression in terms of the acoustic impedance: $P=\delta Z$. Normally this is about 413.3 Pa s/m in 20 degree air, which would give us -4.2 dB for the stellar mass black holes. Which is below the threshold of hearing.

If we instead use $R_S=0.08$ AU for a Sgr A* mass hole pair, now we get 124 dB! That ought to be noticeable... beside the other effects of the merger.

Generally the frequency rises, going up in a chirp, followed by a quick ringing. But the time from the sound becomes noticeable and the merger is likely very quick. Heavy holes merge fast, light ones merge slowly but would be too quiet. However, as Emil pointed out, the frequency is very low for supermassive black holes, maximally about $10^{-2}$ Hz which is below the hearing limit. Stellar mass holes can reach hundreds of Hz, but as discusses above are too quiet at 1 AU.

Induced sound from black hole mergers at 1 AU versus human hearing limit

However, for hole pairs with a combined mass between a few and 200 solar masses the sound intensity does get above the human hearing limit!

Anders Sandberg
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