If one is situated at 50° latitude (meaning north hemisphere) and looks at sunset in the evening, by how many degrees you need to turn leftwards to find the meridian that goes through the point you are situated ? How about if you are situated at the north pole? I would like to look at this at some (any) time point of the year. I had troubles figuring out. I will appreciate your help. Thanks.
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2Related, possible duplicate: https://astronomy.stackexchange.com/q/39670/16685 – PM 2Ring Sep 29 '22 at 09:59
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1Thanks. I looked at that post. I do not think it helped me much to answer my question. – user996159 Sep 29 '22 at 11:03
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It's not that hard to look up tables of sunset angle vs. day-of-year – Carl Witthoft Sep 29 '22 at 12:02
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1It is not about finding a value rather then how you do that. But even after looking at tables I wasn't able to find an answer. – user996159 Sep 29 '22 at 13:21
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The second set of equations on this page will give the setting (or rising) azimuth. You can use that to find any other azimuth. Ships still use this method today to calibrate their compass.https://celestialprogramming.com/risesetalgorithm.html – Greg Miller Sep 29 '22 at 13:33
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Does this answer your question? Using SkyChoord to read in multiple coordinates. – WarpPrime Sep 30 '22 at 03:55