As we all know the usual distance between earth and moon is 384,400 km. But i was thinking how much closer it will be on 14 November 2016, as it will be a supermoon, the brightest and biggest moon in 60 years.
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This is really far too simple a question to be worth keeping in this site. – Carl Witthoft Nov 11 '16 at 12:26
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http://www.space.com/34660-closest-supermoon-full-moon-in-69-years-forecast.html – James K Nov 12 '16 at 07:58
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You may or may not find my https://astronomy.stackexchange.com/questions/19043/how-can-the-next-supermoon-be-analytically-predicted/19052#19052 useful. – Nov 14 '16 at 01:39
2 Answers
Based on some information from this article
http://www.space.com/34515-supermoon-guide.html
The Nov 14 2016 supermooon's expected peak of full phase is on the morning ov Nov 14 at 8:52 AM EST
According to some quick calculations that I performed using PyEphem
and assuming the moon would be viewed by an observer in NYC at 08:52AM EST
0.00236372323707 AU from observer An AU is 1.5 * 10^km
Edit: I needed a better precision for km to AU
http://www.iau.org/static/resolutions/IAU2012_English.pdf
According to this, the AU can be more precisely defined as 149 597 870 700 meters +/- 3 meters
0.00236372323707 * 149 597 870 700 =
353 607 963.19 meters or
~ 353,608 km from earth
here is a quick run through of the inputs I used for the program
>>> moon = ephem.Moon()
>>> nyc = ephem.Observer()
>>> nyc.long, nyc.lat = '-74.0059', '40.7127'
>>> nyc.date = '2016/11/14 08:52:00'
>>> moon.compute(nyc)
>>> print moon.earth_distance
0.00236372323707
Learn more about PyEphem package here http://rhodesmill.org/pyephem/index.html
Note I'm just an amateur and these calculations might not take in certain critical factors. I'm uncertain if PyEphems earth_distance property calculates distance to the moon or the moon's center.
If it does calculate distance to the center of the moon this number could be about ~1700 km smaller.
Given your figure of 384,400 km average, this would put the moon just under
~30 792 km closer to the earth or about 91.98 % of it's normal distance

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How do you multiply by something with two significant figure precision to get something quoted to 7 significant figures? – ProfRob Nov 12 '16 at 11:01
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From where I am on Vancouver Island, western Canada, it will be around 356,500 km.

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1In this case, it would be a good idea stating your source. – SE - stop firing the good guys Nov 12 '16 at 10:52