We'll mount all of them in a same location and connect them to each other (like VLT) so they will combined all the results and will produce some staggering images however my question is, would they be able to produce an image close to the resolution of a 300m optical telescope?
Asked
Active
Viewed 146 times
5
-
θ = 1.22 (λ/D) where θ is the angular resolution(radians), λ is the wavelength of light and D is the diameter of the lens' aperture. – user6760 Apr 17 '15 at 07:09
-
@user6760 That's the key to the answer, just write it up with some explanation and post it as an answer. Don't forget to explain how the "aperture" is determined for interferometry telescopes and the difficulties in using optical interferometry. – Donald.McLean Apr 17 '15 at 13:35
-
@Donald.McLean I'm afraid my knowledge in this area is limited, I hope you may give some insights on interferometry thanks. – user6760 Apr 17 '15 at 13:45
-
Wikipedia has some good articles that talk about the issues (such as https://en.wikipedia.org/wiki/Astronomical_interferometer ). I think the main things are the incredible precision required and how the number of mirrors involved cause significant attenuation of the signal, severely limiting which objects that can be imaged in this way. – Donald.McLean Apr 17 '15 at 14:25
-
Found this. https://www.youtube.com/watch?v=t6TY51JsH4Q&index=14&list=PLX2gX-ftPVXVpN_nZlZ0N1sSYTv0xYoTX Thanks everybody. – AKR Apr 18 '15 at 10:40
-
Would whomever voted to reopen mind adding a comment to explain why? It seems like the duplicate listed is accurate. – Connor Garcia Jan 16 '21 at 19:24