Let $\mathbb{K}$ be an arbitrary field, and $G$ an algebraic group (=group variety?) over this field. A Borel subgroup of $G$ is a connected solvable subgroup variety $B$ of $G$ such that $G/B$ is complete. A parabolic subgroup of $G$ is a subgroup variety $P$ such that $G/P$ is complete.
Given a group $G$ with lie algebra $\mathfrak{g}$, I would expect that a parabolic Lie subalgebra $\mathfrak{p} \leq \mathfrak{g}$ should be a Lie subalgebra which is the Lie algebra of a parabolic subgroup, and likewise for Borel subalgebras $\mathfrak{b} \leq \mathfrak{g}$.
Since distinct groups can obviously have isomorphic Lie algebras, I would expect that there should be a characterization of Borel and parabolic subalgebras in terms of Lie algebra properties alone, without reference to groups.
However, it seems that in every source I've found that discusses Borel and parabolic subalgebras, that they are defined only for finite-dimensional semisimple and complex lie algebras $\mathfrak{g}$. A Borel subalgebra of a complex finite-dimensional semisimple Lie algebra $\mathfrak{g}$ is usually defined to be a maximal solvable subalgebra $\mathfrak{b} \leq \mathfrak{g}$, and a parabolic subalgebra $\mathfrak{p} \leq \mathfrak{g}$ is any subalgebra containing a Borel subalgebra.
Is there a reason for restricting to complex semisimple Lie algebras? Does the definition not work for general Lie algebras?
More generally, what is the relationship between parabolic subgroups and subalgebras? Does the relationship depend at all on the field $\mathbb{K}$ we are working with (characteristic, whether or not it if it is algebraically closed etc.)? Does it depend on the properties of the group (to connected, simply connected, etc.)?
Unfortunately my algebraic geometry knowledge is very minimal. I'm working on stuff in parabolic differential geometry, so I'm hoping to get a better understanding of parabolic subgroups and algebras, especially in the real case.