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The following is a question about Sierpiński's paper "Une démonstration du théorème sur la structure des ensembles de points", (link):

We call a set dense-in-itself if it does not contain any isolated points. An isolated point $x$ is a point for which a neighbourhood exists that does not contain points of the set other than $x$.

Let $C$ be a subset of $\mathbb R$ such that it does not contain any dense-in-itself subsets. Using an enumeration of the countable basis consisting of the balls $B(q,\frac{1}{n})$ we can show (without using the axiom of choice) that there exists a function $\varphi$ that picks a point $p$ in $C$. We can define $\varphi$ by observing that there is at least one ball that only contains one point of $C$. Define $\varphi$ to return the first point in the enumeration of the basic calls such that the ball contains no other points of $C$.

$\varphi$ is a well-defined function on all subsets of $C$.

It seems to me that $\varphi$ therefore is a choice function for $C$ and furthermore that it yields a enumeration of $C$.

In the paper he sets $p_0 = \varphi (C)$ and then goes on to define families $\mathcal K$ of subsets of $C$ with the properties

(i) $\{p_0\} \in \mathcal K$

(ii) if $A_i$ in $\mathcal K$ then $\bigcup_i A_i \in \mathcal K$

(iii) if $E \subsetneq C$ is in $\mathcal K$ then $E \cup \varphi (C \setminus E)$ is also in $\mathcal K$.

He uses $\mathcal K$ to give a proof that $C$ with the above property is enumerable without using the axiom of choice and without using transfinite induction.

My question is: Does effective enumerability of $C$ not immediately follow from the fact that $\varphi$ is a choice function for $C$ (via transfinite induction)?

I suspect I might be using some form of choice in my thoughts without being aware of it. Thanks for your help.

  • There is a link on my profile to the Polish Virtual Library search mask which you may use to obtain access to the paper if you are interested in seeing the whole proof. – Rudy the Reindeer Mar 11 '13 at 12:45
  • I think I'm a bit confused on what $\varphi$ is. What is its domain? What kind of values does it take? – user642796 Mar 11 '13 at 12:47
  • @ArthurFischer In the paper he first proves the claim that there exists a function such that it picks one point from $C$. He calls this function $\varphi$ and the proof uses the enumeration of a basis of $\mathbb R$. Here I think the domain is $C$ and the range is also $C$. He never specifies it explicitly. Yet, in the proof right afterwards, the one about an enumeration of $C$, he uses the expression $\varphi (C \setminus E)$. From this I deduced that from how $C$ is defined and $\varphi$ is constructed, that probably $\varphi$ is $\mathcal P (C) \setminus {\varnothing} \to C$. – Rudy the Reindeer Mar 11 '13 at 12:50
  • Let $\varphi(C)$ be the function that returns the point $c$ that appears first in the enumeration of the basic balls as the only point of $C$ in that ball. Then $\varphi$ is defined for every subset of $C$ (since $C$ is such that it does not contain dense-in-itself subsets). Then define an enumeration of $C$ by transfinite induction: $p_0 = \varphi (C)$. Assume $p_\beta$ are defined for $\beta < \alpha$. And so on. Transfinite induction does not need any form of choice, I think, therefore this should give an enumeration without AC. (even without $AC_\omega$ or DC) – Rudy the Reindeer Mar 11 '13 at 13:06
  • Your (i) is different from Sierpiński’s 1): he simply says that ${p_0}\in\mathcal{K}$. He uses the family of all $A\subseteq C$ such that $p_0\in A$ as an example of a $\mathcal{K}$ satisfying his three conditions. – Brian M. Scott Mar 11 '13 at 15:35
  • @BrianM.Scott Absolutely, thank you. I should have copied it from the paper rather than reproducing it from memory. But I am still stuck on whether his long proof is needed to show that $C$ is effectively enumerable or whether effective enumerability follows immediately (since $\varphi$ is a choice function). Am I right in thinking that transfinite induction is available in ZF? (no sort of choice needed) – Rudy the Reindeer Mar 11 '13 at 15:44
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    Yes, transfinite induction and recursion are both available in ZF. (And yes, $\varphi:\wp(C)\setminus{\varnothing}\to C$.) I want to wade through his argument before making any definite statement, but two possibilities occur to me right away. (1) This is very early; did he have transfinite recursion available as a tool? It’s easy for us: we just index by ordinals. (2) He specifically wants to get an effective enumeration in type $\omega$. – Brian M. Scott Mar 11 '13 at 15:56
  • @BrianM.Scott Thank you very much! It might indeed be that transfinite induction was not available when he wrote this paper. I will see if I can find it out. – Rudy the Reindeer Mar 11 '13 at 16:34
  • @BrianM.Scott Wolfram on Transfinite Induction says that Cantor developed the first transfinite induction methods in the 1880s. The paper I am asking the question about was from 1920. In between, in 1904, Zermelo proved that every set can be well-ordered (using AC which they used to call "Zermelo's Axiom" at the time.) The proof I know which I believe to be Zermelo's original proof, uses transfinite induction. This suggests that Sierpiński knew the technique at the time of writing. – Rudy the Reindeer Mar 11 '13 at 20:17
  • I can easily believe that. I now think that the crux of the matter was his notion of effective. – Brian M. Scott Mar 11 '13 at 20:18
  • (cont'd) Perhaps even by its name which apparently was coined by Hausdorff in 1906. At least according to Wolfram alpha. – Rudy the Reindeer Mar 11 '13 at 20:19
  • @Brian: You might be interested in Zermelo's paper from 1908 about reproving the well-ordering theorem. – Asaf Karagila Mar 11 '13 at 20:46

3 Answers3

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This is intended to supplement the answers already given by expanding on the comments I made yesterday.

Regarding my comment that results were often first proved using transfinite induction, see my 25 November 2005 sci.math post in the thread titled "Transfinite exhaustion" and my 1 September 2006 sci.math post in the thread titled "No irrationals".

Also, you may want to search my posts in sci.math that mention Sierpinski (some, but not all, of these posts can be found using this Google archive search and this Math Forum archive search). For example, in this 3 January 2005 sci.math post in the thread titled "outer measure of the Vitali non-measurable set", I mentioned the following:

An interestingly pathological related result that doesn't seem to be very well known, possibly because the paper in question doesn't appear in the three volume collection of Sierpinski's papers ("Oeuvres Choisies", 1974-1976), is proved in [1]. Sierpinski proves that there exists a pairwise disjoint collection of perfect sets in [0,1] x [0,1] such that if we choose a point from each set in this collection, then we will always wind up with a nonmeasurable set that has outer Lebesgue (planar) measure 1.

[1] Waclaw Sierpinski, "Sur un problème concernant les familles d'ensembles parfaits", Fundamenta Mathematicae 31 (1938), 1-3.

I'll now give some comments about Sierpinski's notion of effectiveness.

Sierpinski used the term effective in a way that is different from the way it is used today or from the way it was used by Borel. Today, the term effective is typically used to imply some form of recursive or computable construction – effective descriptive set theory, effective analog, effective method, effective theory, etc. Borel used the term effective in a somewhat similar way, although Borel's usage was for a less precise constructive metamathematical notion than its usage today.

There does not seem to be much in the literature about Sierpinski's usage of effective, aside from Sierpinski's own words. Moreover, I suspect Sierpinski's explanations have been rendered slightly less precise in the few English translations of his works. I must confess that I do not have a very clear idea of what Sierpinski meant by effective.

From afar, Sierpinski's meaning seems clear. An effective example is one that we can point to (or indicate) or one that we can construct, although not necessarily in a recursive way. However, difficulties seem to arise on closer inspection. Suppose I am able to prove the existence of an object by a method that (always) leads to a fixed outcome, without regard as to whether this was by non-constructive means, by non-recursive means, or by a use of the Axiom of Choice. Have I given an effective example in the sense of Sierpinski? (I think the answer is NO, but I am not really sure.) On the other hand, suppose I give a construction (whatever that means) of an object, but the proof I give that the construction leads to a unique object is itself non-constructive, such as would be the case if the proof of uniqueness was by obtaining a contradiction from the assumption of non-uniqueness. (I think the answer is YES, but I am not really sure.) Finally, suppose I want to prove that a set with property $P$ exists and I do this by proving (1) and (2) (that follow) about the collection $\mathcal C$ of sets that have property $P$: (1) I obtain a contradiction (by possibly non-constructive means) from the assertion that the collection $\mathcal C$ is empty. (2) I obtain a contradiction (by possibly non-constructive means) that the collection $\mathcal C$ contains more than one set. Have I given, in the sense of Sierpinski, an effective example of a set with property $P?$ I think the answer is NO. However, the following comments from p. 57 of Fraenkel/Bar-Hillel's 1958 book (also on p. 68 of the 1973 edition) suggest that the answer may be YES:

Not always need the example be given in a constructive way; its formulation may make use of a non-predicative procedure (pp. 174ff) or be based upon joining an existential proof which shows that there are objects satisfying the definition, to a demonstration that no more than one such object can exist. One might maintain that also in this way an effective example was given.

Note: The discussions about Sierpinski's and Luzin's notions of effectiveness (pp. 54-59) in the 1958 edition are written from a more classical point of view, a view that I believe better captures the spirit of the era in which Luzin and Sierpinski worked, than the corresponding discussion in the 1973 edition (pp. 67-73).

At this point, let's look at what is said in the 1965 English edition of Sierpinski's book Cardinal and Ordinal Numbers.

Chapter II.4: Effectively equivalent sets (pp. 29-30) This discusses what it means for two sets, which have the same cardinality, to be effectively equivalent (i.e. there exists an effective bijection between the sets). To me the discussion does not seem to answer the questions I raised above.

In the remaining two sections of Chapter II Sierpinski proves several theorems, and states several other theorems whose proofs are similar to those he does prove, that involve the behavior of cardinal equivalence and effective cardinal equivalence with unions, Cartesian products, exponentiations of sets, and the Cantor-Bendixson theorem. In all the cases that Sierpinski discusses, the standard proofs of these results are sufficiently "effective" that we can use the same proofs to prove the effective versions. As an example, I will prove the following result: $(A_1$ is effectively equivalent to $A_2)$ and $(B_1$ is effectively equivalent to $B_2)$ implies $({A_1}^{B_1}$ is effectively equivalent to ${A_2}^{B_2}).$ We begin by letting $f_{A}:{A_1} \rightarrow {A_2}$ and $f_{B}:{B_1} \rightarrow {B_2}$ be two effectively defined bijective functions, functions whose existence we are permitted to assume. Given $f \in {A_1}^{B_1},$ we define ${\Phi}(f) \in {A_2}^{B_2}$ by ${\Phi}(f) = {f_A} \circ f \circ {f_{B}}^{-1}.$ This defines a specific function ${\Phi}: {A_1}^{B_1} \rightarrow {A_2}^{B_2},$ a function that we can verify is a bijection, and hence we have shown that ${A_1}^{B_1}$ is effectively equivalent to ${A_2}^{B_2}.$ Note that the usual proof we used (how $\Phi$ is defined) is effective in the sense that any non-effectiveness that could arise in the definition of $\Phi$ can only arise from a non-effectiveness in obtaining the functions $f_A$ and $f_B.$

Chapter III.1: Denumerable and effectively denumerable sets (pp. 38-40) This is also worth looking at. Incidentally, there seems to be a typo in the sequence at the top of p. 39. I believe the sequence should begin as $a_2,$ $a_1,$ $a_4,$ $a_3,$ $a_6,$ $a_5,$ $\ldots$ . There is some discussion of how Borel's notion of effectively denumerable differs from Sierpinski's notion of effectively denumerable on pp. 39-40.

Chapter III.2 – III.5 (pp. 40-47) In these sections Sierpinski establishes the effective denumerability of several naturally occurring sets: the rational numbers (p. 40); any infinite set of non-overlapping (non-degenerate) intervals (pp. 41-42); the set of points of left [or of right; or of unilateral] discontinuity of a strictly increasing real-valued function (p. 43); the set of all finite sequences of rational numbers and the sets ${\mathbb Q}^2,$ ${\mathbb Q}^3,$ $\dots$ and the set of circles with rational radii and centers in ${\mathbb Q}^2$ (pp. 43-44); the set of all finite subsets of an effectively denumerable set (p. 45); the set of algebraic numbers (pp. 46-47).

Chapter III.6 (pp. 48) Here Sierpinski defines the notion effectively non-denumerable as:

$\dots$ we are able to relate to every infinite sequence of the elements of that set an element of the set different from any of the elements of the sequence in question.

Regarding the above definition, Sierpinski cites the following paper:

Petr Sergeevich Novikov, On effectively nondenumerable sets (Russian), Izvestiya Akademii Nauk SSSR, Seriya Matematicheskaya 1939, 35-40. Zbl 24.30103; JFM 65.1169.04 [There is a French summary of Novikov's paper.]

In the paragraphs leading up to the definition of effectively nondenumerable, Sierpinski showed that the set of all infinite sequences of natural numbers has the property stated in the definition.

Chapter IV This deals with sets that have cardinality of the set of real numbers. Unlike the countable version on pp. 30-37 (described above), in this chapter the proofs of some of the theorems involving effectiveness require slightly more care than their non-effective versions.

Chapter VI (pp. 95-96 & 99) This gives some discussion of the Axiom of Choice (AC) and Sierpinski's notion of effectiveness. Incidentally, I think the topmost paragraph on p. 96 is roughly saying that we don't need AC to show $(\forall$ sets in the collection$)(\exists$ choice of an element in the set), but we do need (in general) AC to show $(\exists$ choice of an element in the set$)(\forall$ sets in the collection). That is, assuming AC vs. not assuming AC can be roughly understood as a quantifer reversal in the same way as with assuming uniform continuity vs. assuming continuity.

Sierpinski's 1965 book Cardinal and Ordinal Numbers also discusses various implications that hold between the statements $AC(*,n),$ where $n$ is a positive integer and $AC(*,n)$ (my notion) is the statement that the Axiom of Choice holds for an arbitrary collection of sets each having cardinality $n.$ See my 30 April 2007 sci.math post in the thread titled "I don't like the Axiom of Choice". Incidentally, the following comment (written by me), which appears at the beginning of that post, was about Gregory H. Moore's book Zermelo's Axiom of Choice: Its Origins, Development, and Influence, and thus I was happy to learn from this 1 March 2013 Math Stackexchange post that Moore's book is being reprinted by Dover. In my case, back in Fall 2008 I managed to obtain for about $100 (after an online search) a very good copy of the original 1982 hardcover edition of Moore's book.

Yes, that's the book. I'm shocked that a book like this, with such obvious wide-spread appeal throughout mathematics & logic & philosophy, has gone out of print, and even more surprised that it hasn't been picked up by Chelsea or Dover. There must be some reason those two publishers can't reprint it, because this book is a virtual slam-dunk compared to much of what they reprint.

Whyburn's review of a 1930 book by Sierpinski, a book that was a precursor to Sierpinski's Cardinal and Ordinal Numbers, is also worth reading:

Whyburn, Review of Sierpinski's Lecons sur la Nombres Transfinis, Bulletin of the American Mathematical Society 36 #3 (March 1930), 175-176.

In particular, Whyburn criticizes Sierpinski's views that can also be found on p. 53 (footnote 2) of Sierpinski's 1965 Cardinal and Ordinal Numbers, where Sierpinski says:

The truth of the proposition stating that we are able to indicate an element of the set $A$ depends on the time and on the person who makes it. Logic knows various propositions of this kind, e.g. the propositions: "I am 75 years old", "I am in Paris", "It is Friday to-day".

Incidentally, Sierpinski turned 75 on 14 March 1957 and the Foreword to the earliest edition of the book in which this remark appears is dated November 1957.

See also Zyoiti Suetuna's reviews of two papers by Motokiti Kondo in Journal of Symbolic Logic 17 (1952), pp. 63-64.

Also, the following paper may be of interest. I have a LaTeX file of a carefully prepared English translation of this paper (made with the assistance of someone who has experience with translations), but unfortunately I don't presently have the means to share it with anyone. [The situation described in the last paragraph of this post still holds, but I expect it to change for the better soon.]

Sierpinski, Un exemple effectif d'un ensemble dénombrable de nombres réels qui n'est pas effectivement énumérable [An effective example of a denumerable set of real numbers that is not effectively denumerable], Fundamenta Mathematica 21 (1934), 46-47.

Finally, Volume 1 of the 1966 English edition of Kuratowski's Topology includes a brief discussion of Sierpinski's notion of effectiveness, especially with regard to separable metric spaces and the Cantor-Bendixson theorem. See Section 23.VIII: The concept of effectiveness (p. 254).

Regarding what Kuratowski says, I think his notion of a well defined base of a topology means that we are permitted to assume, in determining whether a proof is effective, that a fixed base has been provided to us in advance. However, we do not assume any of the present-day notions of recursive presentation of the base, such as one finds in Moschovakis' 1980 book Descriptive Set Theory (Chapter 3B:Recursive presentations, pp. 128-135; also on pp. 96-101 of the 2009 2nd edition).

  • @Asaf Karagila: Regarding my comment about the Axiom of Choice for arbitrary collections of sets in which each of the sets has cardinality $n$ (this was included mainly for your benefit), a nice survey of this topic is given in the first few pages of: John Horton Conway, Effective implications between "finite" choice axioms, pp. 439-458 in Mathias/Rogers (editors), Cambridge Summer School in Mathematical Logic, Lecture Notes in Mathematics #337, Springer-Verlag, 1973. MR 50 #12725; Zbl 279.02047 – Dave L. Renfro Mar 13 '13 at 13:53
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My first attempt was completely incorrect. Here is an outline of the proof, missing all of the details, and changing some notations.

  1. Demonstrate, given any scattered set $C$, how to effectively pick an element $\varphi (C) \in C$.
  2. Start with a scattered set $C$.
  3. Letting $p_0 = \varphi ( C )$, consider the smallest family $\mathcal{K}_0$ of subsets of $C$ satisfying the following:

    1. $p_0 \in E$ for all $E \in \mathcal{K}_0$;
    2. $\mathcal{K}_0$ is closed under arbitrary unions;
    3. Given any proper subset $E$ of $C$ in $\mathcal{K}_0$ the set $E \cup \{ \varphi ( C \setminus E ) \}$ belongs to $\mathcal{K}_0$.
  4. Show that $\mathcal{K}_0$ has the additional property that for any $E , G \in \mathcal{K}_0$ either $E \subseteq G$ or $G \subseteq E$ holds.

  5. Picking $p \neq p_0 \in C$ consider $E_p = \bigcup \{ E \in \mathcal{K}_0 : p \notin E \}$; note that $E_p \neq \emptyset$ and $E_p \in \mathcal{K}_0$.

  6. Note that $\varphi ( C \setminus E_p ) = p$ for all $p \neq p_0$ in $C$.

  7. Given distinct $p , p^{\prime} \in C \setminus \{ p_0 \}$ note that either $E_{p} \subseteq E_{p^{\prime}}$ or the reverse inclusion holds. It then follows that either $p^{\prime} \in C \setminus E_{p}$ or $p \in C \setminus E_{p^{\prime}}$ (but not both).
  8. For each $p \in C \setminus \{ p_0 \}$ denote by $n ( p )$ the index of the first sphere $S_n$ for which $S_n \cap C \setminus E_p = \{ p \}$.
  9. Show that for distinct $p , p^\prime \in C \setminus \{ p_0 \}$ we have $n(p) \neq n(p^\prime)$.
  10. Enumerate $C \setminus \{ p_0 \}$ according to the values of $n(p)$. (Add $p_0$ as a first element.)

Addendum: The following would not have been possible without the comments made by Dave L. Renfro, below. (Of course, any errors or mis-statements contained below are solely my fault.)

In his Cardinal and Ordinal Numbers, Sierpiński says the following:

If we can establish a 1-1 correspondence (at least one) between the elements of two given sets $A$ and $B$, then we say that the sets are effectively equivalent, and write $A \mathrel{\text{ef}\mathord{\sim}} B$.

What is meant here is that effective equivalence is a stronger notion than equivalence, where one must only demonstrate that two sets are in 1-1 correspondence without exhibiting any particular correspondence. (I guess this can be read somewhat intuitionistically, but also seems to parallel modern notions.)

More contemporaneous with the paper in question, in Les exemples effectifs et l'axiome du choix [Fund.Math., Tom.2 (1921), 112-118, link] Sierpiński gives the following definition.

Lorsque nous avons défini un objet particular $p$ jouissant de propriétés donnés $P$, nous disons que nous avons un exemple effectif d'un objet jouissant de propriétés $P$.

[Google-Translate-aided translation: When we have defined a particular object $p$ enjoying the properties $P$, we say that we have an effective example of an object enjoying the properties $P$.]

So the effectiveness in the paper linked in the OP is only about exhibiting a particular 1-1 correspondence with the natural numbers.

user642796
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  • Thank you! I have one question regarding "Since C consists of isolated points": the set ${ 1/n \mid n \in \mathbb N_{>0}} \cup {0}$ does not contain any dense-in-itself subsets but $0$ is not an isolated point. That's what I thought. But what am I missing? – Rudy the Reindeer Mar 11 '13 at 13:21
  • My French is "terrible" as well but I will read the rest of the paper and definitely get back to you here with a comment about whether it is actually what he did. – Rudy the Reindeer Mar 11 '13 at 13:22
  • @Matt: You are correct. I'll edit this presently (Just a rephrasing is necessary, I think.) – user642796 Mar 11 '13 at 13:22
  • No hurry, I have to be afk for some hours. I am looking forward to reading your edit later. And thanks a lot for your help, as always. I like your answers. – Rudy the Reindeer Mar 11 '13 at 13:23
  • @Matt: Thank-you very much for pointing out a grave error in my thinking. The proof is a little dense, but I think the above gives an outline of the major points. – user642796 Mar 11 '13 at 17:09
  • Two comments: (1) Rather than "sparse", the appropriate English term is "scattered". (2) I think Sierpinski's notion of effective means a procedure that results in a unique outcome. Thus, to give an effective enumeration of a certain countable set means that the enumeration is defined with sufficient precision so that if two people follow the procedure, both will arrive at the same enumeration. I don't believe computability or recursiveness of the procedure is relevant (or even considered back then). A countable set is effectively enumerable means an effective enumeration for it exists. – Dave L. Renfro Mar 11 '13 at 18:30
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    Two more comments: (3) Sierpinski discusses the notion effectively enumerable a little in his book Cardinal and Ordinal Numbers. (4) Transfinite induction was certainly known at the time. In fact, many papers were written in the 1910s-1930s (this paper, in part, is such a paper) in which authors tried to to prove, without using transfinite induction, various results whose original proofs made use of transfinite induction. The well known Borel hierarchy and various aspects of ordinal arithmetic, among other things, made use of transfinite induction. – Dave L. Renfro Mar 11 '13 at 18:37
  • @DaveL.Renfro: Thank-you for your comments (a correction has already been made above). It almost seems as though these topologists/set-theorists anticipated our modern notion of effectiveness, though perhaps lacked the necessary machinery to make their notion precise. The starting point Sierpiński gives (with an "effective" enumeration of the rational open balls) is so close to how effective descriptive set theory begins that one begins to wonder. – user642796 Mar 11 '13 at 19:00
  • @Dave: I had a hunch that the book would have relevant information. I wish I had a treeware copy. – Asaf Karagila Mar 11 '13 at 20:43
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    @Arthur Fischer and Asaf Karagila: I did a fair amount of digging into the literature about Sierpinski's use of effective in 2007. It's all on my home computer (typed excerpts, reference citations, my own thoughts, etc.), however, which I don't have access to now. I'll look over this material early tomorrow morning, before I come to work, and hopefully I can say more about it then. – Dave L. Renfro Mar 11 '13 at 21:02
  • @Dave: That would be rad. (Also, for future reference, if you comment an answer the answerer is always notified, so it was better to put the @ symbol by my name - that way both myself and Arthur would have been notified and not just him). – Asaf Karagila Mar 11 '13 at 21:14
  • @DaveL.Renfro (your penultimate comment): In this case the answer to my question is: yes, it can be done without transfinite induction but the purpose of the paper is to show it without. Which leaves me with a new question: why did they want to make proofs without transfinite induction at the time? It seems to me that it adds nothing in this case. Once one picks one particular enumeration of the rational balls then the enumeration of any scattered set resulting from transfinite induction is uniquely determined. – Rudy the Reindeer Mar 12 '13 at 07:56
  • @ArthurFischer I still don't know the answer to my question: does the effective enumeration not immediately follow from transfinite induction and the enumeration of the rational balls? Or in other words: is the lengthy proof in this paper needed or can one short cut using transfinite induction? – Rudy the Reindeer Mar 12 '13 at 08:03
  • @Matt: While all countable ordinals are countable (duh) there is no reason to expect that they are all effectively enumerable. (To make an analogy with more modern notions, the countable ordinals above $\omega_1^{\text{CK}}$ (the Church-Kleene ordinal) have no recursive representation as a well-ordering on $\omega$, and so is you want to show that there is a recursive enumeration of a set, you cannot go beyond this point.) [cont...] – user642796 Mar 12 '13 at 08:24
  • [...inued] Unless you could somehow guarantee that a transfinite inductive proof would end at an ordinal that was effectively enumerable, such a proof would not establish an effective enumeration of the set in question. The inductive method I original envisioned would be very close to the Cantor-Bendixson derivative, but you can construct subsets of $\mathbb{R}^n$ with arbitrarily large (but always countable) Cantor-Bendixson rank. – user642796 Mar 12 '13 at 08:24
  • @MattN. Too early. I'm going to delete that worthless comment. Need coffeeee! – user642796 Mar 12 '13 at 08:40
  • @ArthurFischer : ) – Rudy the Reindeer Mar 12 '13 at 08:42
  • @DaveL.Renfro (your penultimate comment): In this case the answer to my question would be: yes, it can be proved using transfinite induction but the purpose of the paper is to show it without. Which leaves me with a new question: Why did they want to make proofs without transfinite induction at the time? It seems to me that once one picks one particular enumeration of the rational balls then the enumeration of any scattered set resulting from transfinite induction is uniquely determined and hence effective. – Rudy the Reindeer Mar 12 '13 at 08:45
  • @ArthurFischer I think your two last comments provide an answer to the OP. I need to think about it some more to properly understand them. – Rudy the Reindeer Mar 12 '13 at 08:48
  • The longer I think about it the less it makes sense: If $C$ is a subset of $\mathbb R$ of cardinality $> \aleph_0$ how could one possibly enumerate it? If an enumeration is an injective map into $\mathbb N$ then $|\mathbb N| = \aleph_0 < |C|$. And certainly in this paper we enumerate using $\mathbb N$ not the ordinals since $\varphi$ is defined using rational base elements. – Rudy the Reindeer Mar 12 '13 at 08:58
  • @Matt: Again, this proof is not just to show that the set is countable (this had previously been shown using transfinite numbers). The proof is meant to in addition construct a bijection between the natural numbers and the set. This could additionally be seen in the light of the various philosophical stances of the time, where constructivists held that to show that an object exists was to actually construct the object in question, and not just show that non-existence would lead to a contradiction. – user642796 Mar 12 '13 at 11:41
  • @ArthurFischer But how can there be a bijection between an uncountable set and the natural numbers? – Rudy the Reindeer Mar 12 '13 at 12:06
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I don't have access to Zermelo's paper at the moment, nor the ability to read French, but the argument you give here seems awfully similar to the one in Zermelo's 1908 paper in which he reproves the well-ordering theorem using $\Theta$-chains.

Despite by best effort I could not find when and where it was proved that $A$ can be well-ordered if and only if $\mathcal P(A)\setminus\{\varnothing\}$ has a choice function. I wouldn't be surprised if that was noted after Sierpinski wrote his paper, but I wouldn't be surprised if that was known before.

In either case, it is possible that Sierpinski is trying to show that $C$ is countable which is more than to say that it is well-orderable.

Asaf Karagila
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    Sierpiński is actually trying to show that $C$ is effectively enumerable. – user642796 Mar 11 '13 at 15:54
  • I'm not sure what effective would mean in 1920. – Asaf Karagila Mar 11 '13 at 16:12
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    At the very least it would be Choiceless. Though "reading" through the paper it doesn't seem to be too far off from our own notions. He is careful to start with an "effective enumeration" of the balls of rational radii centred at points with rational coordinates: L'ensemble des toutes les sphères dont les centres ont des coordonnées rationnelles et dont les rayons sont rationnels, est, comme on sait, effectivement énumérable: nous pouvons done déterminer effectivement une suite infinie $S_1, S_2, S_3, \ldots$ formée de toutes ces sphères. (Google-translate it.) – user642796 Mar 11 '13 at 16:29
  • About the choiceless part, sure. – Asaf Karagila Mar 11 '13 at 16:41
  • It seems you were more correct than myself on this point. – user642796 Mar 11 '13 at 19:50
  • Which point? The effectiveness? It was obvious, I mean recursion theory and computability wouldn't really kick in for another decade... – Asaf Karagila Mar 11 '13 at 20:42